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A241925 (4*s^4 - 3*t^4)*(16*s^8 + 408*s^4*t^4 + 9*t^8), where s > 0, t = 1..s. 3

%I #38 Jul 08 2023 17:05:52

%S 433,648613,1773568,44308593,175549248,230113953,1177246693,

%T 2656718848,7472540053,7264534528,16243007473,25334809408,60857858593,

%U 124911535168,105712890625,141973041573,181487996928,344699541333,719049719808,1194117112629,942546751488

%N (4*s^4 - 3*t^4)*(16*s^8 + 408*s^4*t^4 + 9*t^8), where s > 0, t = 1..s.

%C Sequence lists, in nonincreasing order, the z-values in special solutions to x^4 + y^3 = z^2, that is: A241923(n)^4 + A241924(n)^3 = a(n)^2 (see also Cohen's post in Links section).

%H Vincenzo Librandi, <a href="/A241925/b241925.txt">Table of n, a(n) for n = 1..1000</a>

%H Dario Alpern, <a href="https://www.alpertron.com.ar/SPOW432.HTM">List of first 1602 solutions to a^4 + b^3 = c^2 for increasing values of a, where gcd(a,b,c) = 1</a>.

%H Dario Alpern, Sum of powers, <a href="https://www.alpertron.com.ar/SUMPOWER.HTM#P4_3_2">a^4 + b^3 = c^2</a>.

%H Henri Cohen, <a href="https://groups.google.com/d/msg/sci.math.research/3CIZsALOj3s/JX7U-dobDUcJ">a^m + b^n = c^p (was: Sum of two powers = Square)</a>, post in the newsgroup sci.math.research, Jan 09 1998.

%t Flatten[Table[(4 s^4 - 3 t^4) (16 s^8 + 408 s^4 t^4 + 9 t^8), {s, 10}, {t, s}]]

%o (Magma) [(4*s^4-3*t^4)*(16*s^8+408*s^4*t^4+9*t^8): t in [1..s], s in [1..10]];

%Y Cf. A096741, A241923, A241924.

%K nonn

%O 1,1

%A _Vincenzo Librandi_, May 02 2014

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Last modified June 29 16:57 EDT 2024. Contains 373855 sequences. (Running on oeis4.)