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a(n) = 2*n+2 - A224911(n).
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%I #12 Mar 31 2014 15:50:03

%S 0,1,1,1,3,1,1,3,1,1,3,1,3,5,1,1,3,5,1,3,1,1,3,1,3,5,1,3,5,1,1,3,5,1,

%T 3,1,1,3,5,1,3,1,3,5,1,3,5,7,1,3,1,1,3,1,1,3,1,3,5,7,9,11,13,1,3,1,3,

%U 5,1,1,3,5,7,9

%N a(n) = 2*n+2 - A224911(n).

%C It appears that a(n+2) is successively either one 1 or a string of the odd numbers.

%C Conjecture: the rank of 1's is A005097(n+1). This is another link between Bernoulli numbers and primes via A190339(n).

%C Apparently (essentially) a duplicate of A049653. - _R. J. Mathar_, Mar 30 2014

%e a(0)=2-2=0, a(1)=4-3=1, a(2)=6-5=1, a(3)=8-7=1, a(4)=10-7=3.

%Y Cf. A060308, A005408.

%K nonn

%O 0,5

%A _Paul Curtz_, Mar 04 2014