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Quotients connected with the Banach matchboxes problem: Sum_{i=1..prime(n)-11} 2^(i-1)*binomial(i+4,5)/prime(n) (case 5).
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%I #10 Mar 10 2014 04:28:06

%S 1,625,7451,587687,192856629,1183808479,220742818733,6334029208601,

%T 32973262995075,853235644319439,102411500363403805,

%U 11294927679436544243,53352132931526366997,5415828333647578287211,114722120087477391174007,524320903831521291661817

%N Quotients connected with the Banach matchboxes problem: Sum_{i=1..prime(n)-11} 2^(i-1)*binomial(i+4,5)/prime(n) (case 5).

%C See comment in A238693.

%H V. Shevelev, <a href="http://arxiv.org/abs/1110.5686">Banach matchboxes problem and a congruence for primes</a>, arXiv:1110.5686

%p A238700:=n->sum(2^(i-1)*binomial(i+4,5)/ithprime(n), i=1..ithprime(n) - 11); seq(A238700(n), n=6..25); # _Wesley Ivan Hurt_, Mar 03 2014

%t Table[Sum[2^(i - 1)*Binomial[i + 4, 5]/Prime[n], {i, Prime[n] - 11}], {n, 6, 25}] (* _Wesley Ivan Hurt_, Mar 03 2014 *)

%Y Cf. A238693, A238697, A238698.

%K nonn

%O 6,2

%A _Vladimir Shevelev_, Mar 03 2014

%E More terms from _Peter J. C. Moses_, Mar 03 2014