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%I #31 May 24 2022 02:24:48
%S 0,1,2,5,8,10,11,20,27,33,36,39,42,50,54,57,69,72,75,78,80,84,87,93,
%T 100,101,105,108,110,111,114,135,138,147,162,165,168,174,177,200,219,
%U 222,225,228,231,234,258,267,270,273,276,285,291,294,312
%N Numbers k such that the sum of digits of k^3 is a cube.
%C If k is in the sequence then so is 10*k. - _David A. Corneth_, May 26 2021
%H David A. Corneth, <a href="/A237525/b237525.txt">Table of n, a(n) for n = 1..10866</a>
%F a(n) = A053058(n)^(1/3).
%e 36^3 = 46656. DigitSum(46656) = 27 (also a cube). So, 36 is a member of this sequence.
%o (PARI) isok(n) = ispower(sumdigits(n^3), 3); \\ _Michel Marcus_, Feb 09 2014
%Y Cf. A061910, A007953, A004164, A053058.
%K nonn,base
%O 1,3
%A _Derek Orr_, Feb 09 2014
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