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%I #16 Oct 30 2014 07:06:16
%S 1,8,10,26,44,62,80,100,116,134,152,170,206,224,242,260,314,332,350,
%T 404,422,440,512,530,602,620,710,800,999,1000,1016,1034,1052,1070,
%U 1106,1124,1142,1160,1214,1232,1250,1304,1322,1340,1412,1430,1502,1520,1610
%N Positive integers n such that n^3 divided by the digital sum of n is a cube.
%H Colin Barker, <a href="/A236751/b236751.txt">Table of n, a(n) for n = 1..1000</a>
%e 152 is in the sequence because the digital sum of 152 is 8, and 152^3/8 = 438976 = 76^3.
%o (PARI)
%o s=[]; for(n=1, 3000, d=sumdigits(n); if(n^3%d==0 && ispower(n^3\d, 3), s=concat(s, n))); s
%Y Cf. A007953, A236748, A236749, A236750.
%K nonn,easy,base
%O 1,2
%A _Colin Barker_, Jan 30 2014