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a(n) = tau(n)^n, where tau(n) = A000005(n) = the number of divisors of n.
4

%I #10 Jan 23 2014 00:20:04

%S 1,4,8,81,32,4096,128,65536,19683,1048576,2048,2176782336,8192,

%T 268435456,1073741824,152587890625,131072,101559956668416,524288,

%U 3656158440062976,4398046511104,17592186044416,8388608,4722366482869645213696,847288609443,4503599627370496

%N a(n) = tau(n)^n, where tau(n) = A000005(n) = the number of divisors of n.

%H Jaroslav Krizek, <a href="/A236284/b236284.txt">Table of n, a(n) for n = 1..100</a>

%F a(n) = A000005(n)^n.

%e a(4) = tau(4)^4 = 3^4 = 81.

%t Table[DivisorSigma[0, n]^n, {n, 1000}]

%o (PARI) s=[]; for(n=1, 30, s=concat(s, sigma(n, 0)^n)); s \\ _Colin Barker_, Jan 22 2014

%Y Cf. A000005 (tau(n)), A062758 (n^tau(n)), A217872 (sigma(n)^n), A236285 (tau(n)^sigma(n)), A236286.

%K nonn

%O 1,2

%A _Jaroslav Krizek_, Jan 21 2014