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A234605
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a(n+1) is next smallest cube ending with a(n), initial term is 0.
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6
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OFFSET
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1,2
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COMMENTS
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a(6) is too large to include (contains 124 digits).
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LINKS
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FORMULA
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a(n) = (sum_{i=0..n-1} 10^((3^i+1)/2))^3. - Max Alekseyev, Jan 07 2015
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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