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2^n mod n^3.
2

%I #6 Dec 13 2013 16:39:07

%S 0,4,8,16,32,64,128,256,512,24,717,640,1601,2664,2393,0,3334,5536,

%T 3004,576,4166,9640,5545,8704,7557,3696,19034,6400,20244,5824,29204,0,

%U 21293,12176,13493,40960,41146,25008,16154,11776,55680,56008,20642,79040,14957,1016

%N 2^n mod n^3.

%F a(n) = A000079(n) mod A000578(n).

%o (Python)

%o for n in range(1,100): print str(2**n % n**3)+',',

%Y Cf. A000079, A000578, A066606, A066607.

%Y Cf. A233441, A233471.

%K nonn

%O 1,2

%A _Alex Ratushnyak_, Dec 09 2013