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a(n) = floor(n^n / 3^n).
1

%I #12 Mar 25 2025 14:49:54

%S 1,0,0,1,3,12,64,376,2557,19683,169350,1610592,16777216,189970982,

%T 2323244584,30517578125,428528437130,6405755132013,101559956668416,

%U 1702215647540101,30072865982171749,558545864083284007,10880062101736647492,221794805104450672070

%N a(n) = floor(n^n / 3^n).

%o (Python)

%o for n in range(33): print(n**n // 3**n, end=', ')

%Y Cf. A000244, A000312, A233203.

%K nonn

%O 0,5

%A _Alex Ratushnyak_, Dec 08 2013