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a(n) = largest m such that 1, 2, ..., m divide n-th Fibonacci number; a(n) = A055874(A000045(n)).
5

%I #14 Aug 11 2018 22:02:02

%S 1,1,2,1,1,2,1,1,2,1,1,4,1,1,2,1,1,2,1,1,2,1,1,4,1,1,2,1,1,2,1,1,2,1,

%T 1,4,1,1,2,1,1,2,1,1,2,1,1,4,1,1,2,1,1,2,1,1,2,1,1,6,1,1,2,1,1,2,1,1,

%U 2,1,1,4,1,1,2,1,1,2,1,1,2,1,1,4,1,1,2,1,1,2,1,1,2,1,1,4,1,1,2,1,1,2,1,1,2,1,1,4,1,1,2,1,1,2,1,1,2,1,1,12

%N a(n) = largest m such that 1, 2, ..., m divide n-th Fibonacci number; a(n) = A055874(A000045(n)).

%C It seems that the records occur at the positions given by A233283: 1, 3, 12, 60, 120, 840, 2520, 12600, ...

%C The corresponding record values begin as 1, 2, 4, 6, 12, 16, 24, 36, ... (maybe A007416?).

%H Antti Karttunen, <a href="/A233284/b233284.txt">Table of n, a(n) for n = 1..12600</a>

%Y Differs from A233285 for the first time at n=120, where a(120)=12, while A233285(120)=7.

%Y Cf. A055874, A000045, A001175-A001177, A233283, A007416.

%K nonn

%O 1,3

%A _Antti Karttunen_, Dec 12 2013