%I #23 Nov 08 2016 07:35:17
%S 1512,2688,6048,10752,13608,24192,37800,43008,54432,67200,74088,96768,
%T 122472,131712,151200,172032,182952,217728,255528,268800,296352,
%U 325248,340200,387072,436968,454272,489888,526848,545832,604800,666792,688128,731808,776832
%N Integer areas of orthic triangles of integer-sided triangles.
%C Given a triangle ABC, the triangle H1H2H3 whose vertices are endpoints of the altitudes from each of the vertices of ABC is called the orthic triangle, or sometimes the altitude triangle. The three lines AH1, BH2, and CH3 are concurrent at the orthocenter H of the triangle ABC.
%C The area of the orthic triangle is given by S'= abc|cos A cos B cos C|/2R where a, b, c are the integer sides of ABC and R is the circumradius of ABC.
%C The lengths of the legs of the orthic triangle are given by
%C a' = a|cos A| = a|b^2+c^2-a^2|/2bc;
%C b' = b|cos B| = b|c^2+a^2-b^2|/2ac;
%C c' = c|cos C| = c|a^2+b^2-c^2|/2ab.
%C Property of this sequence:
%C It seems that all triangles are isosceles of the form (a, a, b) with a < b, and each associated orthic triangle is also of the form (h1, h1, h2) but with h1> h2(see the table below). It seems also that if the area of the orthic triangle is an integer, then the sides are integers.
%C The following table gives the first values (S’, S, a, b, c, h1, h2, h3) where S' is the area of the orthic triangles, S is the area of the triangles ABC, a, b, c the integer sides of the triangles ABC and h1, h2, h3 are the integer sides of the orthic triangles.
%C ******************************************************
%C * S’ * S * a * b * c * h1 * h2 * h3 *
%C ******************************************************
%C * 1512 * 7500 * 125 * 125 * 150 * 75 * 75 * 42 *
%C * 2688 * 7500 * 125 * 125 * 200 * 100 * 100 * 56 *
%C * 6048 * 30000 * 250 * 250 * 300 * 150 * 150 * 84 *
%C * 10752 * 30000 * 250 * 250 * 400 * 200 * 200 * 112 *
%C * 13608 * 67500 * 375 * 375 * 450 * 225 * 225 * 126 *
%C * 24192 * 67500 * 375 * 375 * 600 * 300 * 300 * 168 *
%C * 24192 * 120000 * 500 * 500 * 600 * 300 * 300 * 168 *
%C * 37800 * 187500 * 625 * 625 * 750 * 375 * 375 * 210 *
%C * 43008 * 120000 * 500 * 500 * 800 * 400 * 400 * 224 *
%C * 54432 * 270000 * 750 * 750 * 900 * 450 * 450 * 252 *
%C .............................
%D H. S. Coxeter and M. Greitzer, The Orthic Triangle, §1.6 in Geometry Revisited, Washington DC, Math. Assoc. Amer., pp. 9 and 16-18, 1967.
%D R. Honsberger, The Orthic Triangle, §2.3 in Episodes in Nineteenth and Twentieth Century Euclidean Geometry, Washington DC, Math. Assoc. Amer., pp. 21-25, 1995.
%H C. Kimberling, <a href="http://www.jstor.org/stable/2690608">Central Points and Central Lines in the Plane of a Triangle</a>, Math. Mag. 67, 163-187, 1994.
%H Eric W. Weisstein, <a href="http://mathworld.wolfram.com/OrthicTriangle.html">MathWorld: Orthic Triangle</a>
%F Empirical g.f.: -168*x*(9*x^10 -2*x^9 +22*x^8 +6*x^7 +11*x^6 +52*x^5 +11*x^4 +6*x^3 +22*x^2 -2*x +9) / ((x -1)^3*(x +1)*(x^2 -x +1)^2*(x^2 +x +1)^2). - _Colin Barker_, Oct 22 2013
%e 1512 is in the sequence because the orthic triangle (h1, h2, h3) associated with the triangle (a, b, c) = (125, 125, 150) is the triangle (75, 75, 42) where:
%e a' = a|cos A| = a|b^2+c^2-a^2|/2bc = 75;
%e b' = b|cos B| = b|c^2+a^2-b^2|/2ac = 75;
%e c' = c|cos C| = c|a^2+b^2-c^2|/2ab = 42.
%e and the area is given by Heron's formula: sqrt((96*(96-75)*(96-75)*(96-42)) = 1512.
%e It is possible to use also the formula S'= abc|cos A cos B cos C|/2R = h1*h2*h3/2R with R = a*b*c/4S where S is the area of the triangle (a, b, c) and S' the area of the orthic triangle. Hence S' = h1*h2*h3*2*S/a*b*c = 75*75*42*2*7500/(125*125*150) = 1512.
%t nn=200; lst={}; Do[s=(a+b+c)/2; If[IntegerQ[s], area2=s (s-a) (s-b) (s-c); aa=Abs[((b^2+c^2-a^2)*(c^2+a^2-b^2)*(a^2+b^2-c^2))/(4*(a^2*b^2*c^2))]; If[0<area2 && aa>0 && IntegerQ[Sqrt[area2]*aa], AppendTo[lst, Sqrt[area2]*aa]]], {a,nn}, {b,a}, {c,b}]; Union[lst]
%K nonn
%O 1,1
%A _Michel Lagneau_, Oct 18 2013
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