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%I #14 Sep 19 2013 12:59:32
%S 1,4,19,91,379,436,2089,7561,8644,10009,36001,47956,144019,150841,
%T 198379,229771,821089,1100899,3009259,3419716,3933001,4554019,5274724,
%U 14328091,25272721,54726841,57312379,60034339,68221876,74727379,77994811,90262009,104544004
%N Generalized Markoff numbers: union of numbers a, b, c, d, e satisfying the Markoff(5) equation a^2 + b^2 + c^2 + d^2 + e^2 = 5*a*b*c*d*e.
%e a(1)=1 since (1, 1, 1, 1, 1) is a solution to a^2 + b^2 + c^2 + d^2 + e^2 = 5*a*b*c*d*e. a(2)=4 since (4, 1, 1, 1, 1) is a solution. a(3)=19 since (19,4,1,1,1) is a solution. a(n) is the n-th leading term (that is a's) among all the solutions with a >= b >= c >= d >= e.
%K nonn
%O 1,2
%A _Shanzhen Gao_, Sep 17 2013