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%I #15 Feb 05 2014 20:56:03
%S 2,7,26,55,97,362,433,727,1351,1538,3079,3409,5042,10087,18817,20330,
%T 26839,43009,70226,75601,95258,140455,172369,190519,211303,262087,
%U 338353,529255,568513,978122,1048951,1202714,1354753,1663585,1956247,2368519,3650401,3913730,4741658,5904386,7861777,9483319
%N Generalized Markoff numbers: largest number a in a 5-tuple a >= b >= c >= d >= e satisfying the Markoff(5) equation a^2 + b^2 + c^2 + d^2 + e^2 = 4*a*b*c*d*e.
%e a(1)=2 since (2, 1, 1, 1, 1) is a solution of a^2 + b^2 + c^2 + d^2 + e^2 = 4*a*b*c*d*e. a(2)=7 since (7, 2, 1, 1, 1) is a solution. a(3)=26 since (26,7,1,1,1) is a solution.
%K nonn
%O 1,1
%A _Shanzhen Gao_, Sep 17 2013
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