login
A228017
Numbers n divisible by the sum of any k-subset of digits of n with k >= 1.
0
1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 24, 36, 48
OFFSET
1,2
COMMENTS
No additional terms less than 20000000. - T. D. Noe, Aug 14 2013
Terms > 9 must be even since any pair of digits has an even subset. Since terms must also be zeroless, they cannot be divisible by 5, which means no further terms could have 5 or more digits by the Pigeonhole Principle. Therefore, this sequence is complete. - Charlie Neder, May 31 2019
EXAMPLE
48 is here because 48 is divisible by 4, 8, and 4+8.
MATHEMATICA
okQ[n_] := Module[{s = Total /@ Rest[Subsets[IntegerDigits[n]]]}, ! MemberQ[s, 0] && And @@ IntegerQ /@ (n/s)]; Select[Range[10000], okQ] (* T. D. Noe, Aug 14 2013 *)
CROSSREFS
Subset of A051004 and of A346535.
Sequence in context: A059043 A259236 A138141 * A346535 A227224 A236750
KEYWORD
nonn,base,fini,full
AUTHOR
Derek Orr, Aug 02 2013
STATUS
approved