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a(n) = |A020497(n) - prime(n+4) + 10|.
0

%I #8 Jun 10 2013 21:35:27

%S 0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,4,2,4,2,2,0,2,4,12,12,4,6,4,8,2,6,6,

%T 4,2,0,0,6,2,4,2,8,0,2,4,2,4,8,10,6,6

%N a(n) = |A020497(n) - prime(n+4) + 10|.

%C Approximation of A020497(n) by function of the form prime(n+k) - c, where k,c are constants. The choice k=4 is stipulated by removing 2 and 5 from the considered prime constellations and 11 is chosen as the first prime (for n=1), since the second constellation {11,13} should be a twin pair. The choice c=10 corresponds to a(0) = 0.

%C a(n) = 0 for n=1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,22,36,37,43,...

%Y Cf. A020497.

%K nonn

%O 1,6

%A _Vladimir Shevelev_, Jun 10 2013