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a(n) = floor((n-1)!/n).
4

%I #18 Aug 15 2023 21:04:03

%S 1,0,0,1,4,20,102,630,4480,36288,329890,3326400,36846276,444787200,

%T 5811886080,81729648000,1230752346352,19760412672000,336967037143578,

%U 6082255020441600,115852476579840000,2322315553259520000,48869596859895986086

%N a(n) = floor((n-1)!/n).

%C (h-1)!/h is integer if h belongs to A056653.

%H Vincenzo Librandi, <a href="/A226198/b226198.txt">Table of n, a(n) for n = 1..200</a>

%t Table[Quotient[(n - 1)!, n], {n, 25}]

%o (Magma) [Floor(Factorial(n-1)/n): n in [1..25]];

%Y Cf. A001048 ((n+1)!/n), A056653, A091330 (floor((p-1)!/p), where p is prime), A175787 (prime numbers together with 4).

%K nonn

%O 1,5

%A _Vincenzo Librandi_, May 31 2013

%E Edited by _Bruno Berselli_, May 31 2013