OFFSET
0,2
COMMENTS
Conjecture: a(n)/6^n is always a positive odd integer. Moreover, for any integers r > 1 and n >= 0, the number a(r,n)/2^n is a positive odd integer, where a(r,n) denotes the Hankel determinant |f(r,i+j)|_{i,j=0,...,n} with f(r,k) = sum_{j=0}^k C(k,j)^r.
On Aug 20 2013, Zhi-Wei Sun made the following conjecture: If p is a prime congruent to 1 mod 4 but p is not congruent to 1 mod 24, then p divides a((p-1)/2).
LINKS
Zhi-Wei Sun, Table of n, a(n) for n = 0..25
EXAMPLE
a(0) = 1 since f(0+0) = 1.
MATHEMATICA
f[n_]:=Sum[Binomial[n, k]^3, {k, 0, n}]; a[n_]:=Det[Table[f[i+j], {i, 0, n}, {j, 0, n}]]; Table[a[n], {n, 0, 10}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Zhi-Wei Sun, Aug 14 2013
STATUS
approved