%N Numbers k such that antisigma(x) = antisigma(x+1) = k has solution.
%C Antisigma(n) = A024816(n) = the sum of the nondivisors of n that are between 1 and n.
%C Conjecture: also numbers k such that antisigma(n) = antisigma(m) = k has solution for distinct numbers n and m. - _Jaroslav Krizek_, Nov 10 2013
%e 36844389 is in the sequence because 36844389 = antisigma(8585) = antisigma(8586).
%Y Cf. A067816 (numbers n such that antisigma(n) = antisigma(n+1)).
%A _Jaroslav Krizek_, Jul 26 2013