|
%I #13 Aug 17 2019 02:18:17
%S 3,6,6,5,1,9,1,8,2,1,3,5,2,4,8,9,7,4,8,2,8,2,7,5,9,1,8,8,5,1,2,9,3,4,
%T 6,7,8,5,9,5,7,0,3,8,9,3,1,6,4,0,7,5,8,7,0,4,5,7,0,8,3,1,5,1,2,8,3,3,
%U 4,8,7,3,2,5,3,9,0,9,4,6,1,5,5,8,5,5,8,3,3,3,4,5,7,5,0,9,9,8,1,8
%N 10-adic integer x such that x^9 = 7/9.
%C This is the 10's complement of A225453.
%H Seiichi Manyama, <a href="/A225462/b225462.txt">Table of n, a(n) for n = 0..10000</a>
%e 3^9 == -7 (mod 10).
%e 63^9 == -77 (mod 10^2).
%e 663^9 == -777 (mod 10^3).
%e 5663^9 == -7777 (mod 10^4).
%e 15663^9 == -77777 (mod 10^5).
%e 915663^9 == -777777 (mod 10^6).
%o (PARI) n=0;for(i=1,100,m=(2*(10^i-1)/9)+1;for(x=0,9,if(((n+(x*10^(i-1)))^9)%(10^i)==m,n=n+(x*10^(i-1));print1(x", ");break)))
%o (PARI) N=100; Vecrev(digits(lift(chinese(Mod((7/9+O(2^N))^(1/9), 2^N), Mod((7/9+O(5^N))^(1/9), 5^N)))), N) \\ _Seiichi Manyama_, Aug 07 2019
%Y Cf. A225453.
%K nonn,base
%O 0,1
%A _Aswini Vaidyanathan_, May 11 2013
|
