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10-adic integer x such that x^9 = -3.
1

%I #12 Aug 16 2019 14:03:39

%S 7,1,5,1,3,4,3,5,3,5,4,4,7,6,3,4,4,6,3,5,0,2,0,0,2,4,3,9,2,4,1,1,0,6,

%T 2,2,8,0,9,6,8,9,1,6,3,8,5,7,2,4,3,2,6,1,2,1,1,2,6,5,7,1,9,9,1,3,3,0,

%U 3,5,0,5,4,4,4,3,2,9,3,4,8,2,6,3,5,3,6,6,5,3,6,9,0,2,2,8,3,7,2,8

%N 10-adic integer x such that x^9 = -3.

%C This is the 10's complement of A225456.

%H Seiichi Manyama, <a href="/A225459/b225459.txt">Table of n, a(n) for n = 0..10000</a>

%e 7^9 == -3 (mod 10).

%e 17^9 == -3 (mod 10^2).

%e 517^9 == -3 (mod 10^3).

%e 1517^9 == -3 (mod 10^4).

%e 31517^9 == -3 (mod 10^5).

%e 431517^9 == -3 (mod 10^6).

%o (PARI) n=0;for(i=1,100,m=(10^i-3);for(x=0,9,if(((n+(x*10^(i-1)))^9)%(10^i)==m,n=n+(x*10^(i-1));print1(x", ");break)))

%o (PARI) N=100; Vecrev(digits(lift(chinese(Mod((-3+O(2^N))^(1/9), 2^N), Mod((-3+O(5^N))^(1/9), 5^N)))), N) \\ _Seiichi Manyama_, Aug 07 2019

%Y Cf. A225456.

%K nonn,base

%O 0,1

%A _Aswini Vaidyanathan_, May 11 2013