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Number of solutions to rev(x^2) = rev(x)^2 with at most n digits, where the function rev(x) reverses the digits of x.
2

%I #9 May 23 2013 15:49:56

%S 4,10,25,64,154,363,820,1811,3873,8161,16682,33757,66865,130938,

%T 251983,480794,903982,1685564,3106009,5677864,10276936,18464659,

%U 32891188,58169965,102136773,178096365,308593320,531191385,909227947,1546356486,2617639293

%N Number of solutions to rev(x^2) = rev(x)^2 with at most n digits, where the function rev(x) reverses the digits of x.

%C Numbers (other than 0) that end in zero are excluded.

%H David Radcliffe, <a href="/A225301/a225301.py.txt">Python code for calculating a(n).</a>

%F Equals one more than the partial sums of A098701.

%e For n = 2 the a(2) = 10 solutions are 0, 1, 2, 3, 11, 12, 13, 21, 22, 31.

%Y Cf. A085305, A061909.

%K nonn,base

%O 1,1

%A _David Radcliffe_, May 05 2013