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%I #11 Dec 02 2017 10:08:53
%S 2,4,6,9,11,14,16,19,21,24,26,29,31,34,36,38,41,43,46,48,51,53,56,58,
%T 61,63,66,68,71,73,75,78,80,83,85,88,90,93,95,98,100,103,105,108,110,
%U 112,115,117,120,122,125,127,130,132,135,137,140,142,145,147,149
%N Floor(1/f(x^(1/n))) for x = 3/2, where f computes the fractional part.
%H Melvyn B. Nathanson, <a href="http://dx.doi.org/10.4169/amer.math.monthly.120.05.409">On the fractional parts of roots of positive real numbers</a>, Amer. Math. Monthly, 120 (2013), 409-429.
%F a(n) = floor(n/log(3/2)-1/2) for n>1. - _Andrey Zabolotskiy_, Dec 01 2017
%t th = 3/2; t = Table[Floor[1/FractionalPart[th^(1/n)]], {n, 100}]
%Y Cf. A224996, A224997, A224998, A001651, A047211, A047203, A047290, A047332.
%K nonn,easy
%O 1,1
%A _T. D. Noe_, Apr 26 2013