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A224499 Numbers n such that if 2n+1 divides 2^n+1 then 2(n+1)+1 also divides 2^(n+1)+1. 0

%I

%S 1,5,29,53,89,113,173,209,329,413,509,545,713,725,809,833,893,965,

%T 1013,1133,1169,1625,1649,1685,1733,1769,1925,2009,2045,2129,2273,

%U 2393,2465,2549,2825,2933,3065,3149,3329,3389,3413,3473,3605,3653,3665,3773

%N Numbers n such that if 2n+1 divides 2^n+1 then 2(n+1)+1 also divides 2^(n+1)+1.

%C First of a pair of consecutive Curzon numbers, where Curzon numbers are given by A224486.

%t CuQ[n_] := IntegerQ[(2^n + 1)/(2*n + 1)]; Select[Range[4000], CuQ[#] && CuQ[# + 1] &]

%Y Cf. A224486.

%K nonn

%O 1,2

%A _Jayanta Basu_, Apr 08 2013

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Last modified September 22 16:44 EDT 2020. Contains 337291 sequences. (Running on oeis4.)