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%I #5 Sep 18 2016 12:23:58
%S 21,189,525,567,1134,1365,1533,4599,4725,9198,10773,12285,34125,36855,
%T 38325,73710,86037,87381,96957,98301,269325,294903,307125,589806,
%U 688149,700245,774333,786429,2150925,2184525,2322999,2359287,2423925,2457525,4645998,4718574,5505045,5515797,5592405,5603157,6193341,6204093,6280701,6291453
%N Numbers n with the property that if the base-8 representation of n is read backwards, the result is an integral multiple of n.
%C A217742 is a subsequence.
%C The multiples that occur are 2, 3, 5, 7 (cf. A222817-A222820).
%e n = 525 (base 10) = 1015 (base 8). Reading this backwards we get 5101 (base 8) = 2625 (base 10) = 5*n, so 525 is in the sequence.
%t b8rQ[n_]:=Module[{c=FromDigits[Reverse[IntegerDigits[n,8]],8]},c/n>1 && IntegerQ[c/n]]; Select[Range[63*10^5],b8rQ] (* _Harvey P. Dale_, Sep 18 2016 *)
%Y Cf. A214927, A217742, A223089, A222817-A222820.
%K nonn,base
%O 1,1
%A _N. J. A. Sloane_, Mar 23 2013