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A220990 a(n) = 12^(2n+1) + 6 * 12^n + 1: the right Aurifeuillian factor of 12^(6n+3) + 1. 12

%I #20 Feb 14 2024 02:25:44

%S 19,1801,249697,35842177,5159904769,743009863681,106993223294977,

%T 15407021789577217,2218611109320327169,319479999401581608961,

%U 46005119909741205651457,6624737266953695061344257,953962166440743626203987969

%N a(n) = 12^(2n+1) + 6 * 12^n + 1: the right Aurifeuillian factor of 12^(6n+3) + 1.

%C The corresponding left Aurifeuillian factor is A220989.

%H Wikipedia, <a href="http://en.wikipedia.org/wiki/Cunningham_project">Cunningham Project</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (157,-1884,1728).

%F Aurifeuillian factorization: 12^(6n+3) + 1 = (12^(2n+1) + 1) * A220989(n) * a(n).

%F G.f.: -(2736*x^2-1182*x+19) / ((x-1)*(12*x-1)*(144*x-1)). - _Colin Barker_, Jan 03 2013

%t Table[12^(2n+1) + 6 * 12^n + 1, {n, 0, 10}]

%t LinearRecurrence[{157,-1884,1728},{19,1801,249697},20] (* _Harvey P. Dale_, Mar 26 2022 *)

%o (PARI) a(n)=12^(2*n+1)+6*12^n+1 \\ _Charles R Greathouse IV_, Sep 28 2015

%Y Cf. A092440, A085601, A220978, A198410, A220979-A220989.

%K nonn,easy

%O 0,1

%A _Stuart Clary_, Dec 27 2012

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Last modified April 23 13:51 EDT 2024. Contains 371914 sequences. (Running on oeis4.)