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A219087 a(n) = floor((n + 1/2)^(4/3)). 2

%I #6 Aug 29 2021 16:02:19

%S 0,1,3,5,7,9,12,14,17,20,22,25,29,32,35,38,42,45,48,52,56,59,63,67,71,

%T 75,79,83,87,91,95,99,103,107,112,116,121,125,130,134,139,143,148,152,

%U 157,162,167,172,176,181,186,191,196,201,206,211,216,221,227

%N a(n) = floor((n + 1/2)^(4/3)).

%C a(n) is the number k such that {k^p} < 1/2 < {(k+1)^p}, where p = 3/4 and { } = fractional part. Equivalently, the jump sequence of f(x) = x^(3/4), in the sense that these are the nonnegative integers k for which round(k^p) < round((k+1)^p). For details and a guide to related sequences, see A219085.

%H Clark Kimberling, <a href="/A219087/b219087.txt">Table of n, a(n) for n = 0..10000</a>

%F a(n) = floor((n + 1/2)^(4/3)).

%t Table[Floor[(n + 1/2)^(4/3)], {n, 0, 100}]

%Y Cf. A219085, A219086.

%K nonn,easy

%O 0,3

%A _Clark Kimberling_, Jan 01 2013

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Last modified September 18 18:03 EDT 2024. Contains 376002 sequences. (Running on oeis4.)