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A218720 a(n) is smallest number such that a(n)^2 + 1 is divisible by 101^n. 0

%I #4 Nov 05 2012 12:20:58

%S 0,10,515,296344,35764191,1108900220,316411915250,47023298541694,

%T 3156215819652023,310872228812491206,28124944860980892220,

%U 3783840171259076226254,208193145695151069244665,19364218657938636320485082,663491749602035014400202724

%N a(n) is smallest number such that a(n)^2 + 1 is divisible by 101^n.

%e a(3) = 296344 because 296344^2+1 = 101 ^ 3 * 85237.

%t b=10;n101=101;jo=Join[{0,b},Table[n101=101*n101;b=PowerMod[b, 101,n101];b=Min[b,n101-b],{99}]]

%Y Cf. A002522, A049532, A034939, A218709, A218710, A218712, A218713, A218714, A218715, A218716, A218717, A218718, A218719.

%K nonn

%O 0,2

%A _Michel Lagneau_, Nov 04 2012

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