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%I #8 Oct 02 2012 12:16:44
%S 24,24,24,24,36,24,24,24,24,36,24,24,24,24,36,24,24,24,24,36,24,24,24,
%T 24,36,24,24,24,24,36,24,24,24,24,60,24,24,24,24,36,24,24,24,24,36,24,
%U 24,24,24,36,24,24,24,24,36,24,24,24,24,36,24,24,24,24,36
%N a(n) = m/n where m is the least number divisible by n such that phi(m) = phi(m+6n).
%H Michel Marcus, <a href="/A217140/b217140.txt">Table of n, a(n) for n = 1..1000</a>
%e A179188(1)=24 is divisible by 1 and the quotient is 24, so a(1)=24.
%e A217139(1)=48 is divisible by 2 and the quotient is 24, so a(2)=24.
%e The first solution to phi(n)=phi(n+18) to be divisible by 3 is 72 and the quotient is 24, so a(3)=24.
%Y Cf. A007015, A179188, A217139, A217141, A217068.
%K nonn
%O 1,1
%A _Michel Marcus_ and _Jonathan Sondow_, Oct 01 2012