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10's-complement of A216161.
1

%I #5 Sep 02 2012 18:00:08

%S 7,7,7,5,6,4,2,6,8,2,9,5,5,8,7,3,6,5,8,2,2,8,9,0,3,1,5,6,3,8,1,6,8,5,

%T 3,4,0,8,0,1,7,7,8,5,6,4,4,4,6,6,0,0,9,0,8,5,1,8,4,1,7,3,0,3,2,3,3,6,

%U 3,0,0,7,0,7,5,7,5,0,6,6,8,7,1,5,0,3,2,4,4,8,4,1,0,3,2,8,8,7,3,3,9,0,5,5,7,0

%N 10's-complement of A216161.

%C 11^50 ends in 23001

%C 11^500 ends in 2230001

%C 11^5000 ends in 422300001

%C 11^50000 ends in 34223000001

%C The last digits before the zeros tend to converge.

%F a(n) = 10 - [{11^(5*10^n) mod 10^(2n+2) - 1}/(10^(2n+1)) mod 10].

%Y Cf. A216161, A007185, A016090, A091663, A018248, A091664, A018247.

%K nonn

%O 1,1

%A _V. Raman_, Sep 02 2012