A215508 Smallest m such that the period of the continued fraction of sqrt(m) is A215485(n); records of A013646.

1, 2, 3, 41, 58, 106, 193, 337, 586, 949, 1061, 1117, 1153, 1249, 1669, 2381, 3733, 5857, 6577, 6781, 8389, 11173, 14293, 15817, 17137, 17209, 23017, 37921, 38377, 46261, 47293, 56929, 82561, 90121, 113173, 122401, 148957, 151057, 161149, 163729, 193873, 206209, 225769, 322513, 497473, 576529, 676129, 686893, 706621, 862921, 946489, 992281, 1032649, 1198081, 1597033, 1655677, 1779409, 1930021, 2299489, 2367481, 2584081, 3209281, 3528409, 3933073, 4068241, 4160521, 4283689, 4726009, 4833901

Offset

0,2

Comments

The continued fractions of these numbers have the "hard to get" lengths listed in sequence A215485. They fill the last gaps in the table when computing A013646.

Links

Patrick McKinley, Table of n, a(n) for n = 0..253

Formula

a(n) = A013646(A215485(n)). - Pontus von Brömssen, Nov 24 2024

Example

The lengths of the continued fractions of sqrt(1), sqrt(2), sqrt(3) and sqrt(41) are 0, 1, 2 and 3 respectively. The rest of the sequence follows A215485 similarly.

Crossrefs

Cf. A013646, A215485.

Sequence in context: A330293 A302687 A280893 * A215385 A215389 A215154

Adjacent sequences: A215505 A215506 A215507 * A215509 A215510 A215511

Keyword

nonn

Author

Patrick McKinley, Aug 13 2012

Status

approved