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%I #7 Aug 15 2012 11:00:47
%S 1,2,3,3,4,3,2,4,5,4,5,3,2,5,3,5,6,5,4,4,3,5,6,3,2,6,2,5,3,3,4,6,7,6,
%T 5,5,7,4,4,4,3,3,7,5,3,6,7,3,2,7,2,6,2,7,5,5,3,3,3,7,4,4,5,7,8,7,6,6,
%U 5,5,5,5,4,7,4,4,8,4,4,4,3,3,8,3,5,7,5,5,3,3,6,6,3,7,8,3,2,8,2,7
%N a(n) = A215467(2n+1).
%C The other bisection of A215467, {A215467(2n)}, is the same as A215467 itself.
%Y Cf. A215467.
%K nonn,base
%O 0,2
%A _N. J. A. Sloane_, Aug 11 2012
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