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A214709
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Least m>0 such that n!-m and 2^n-m are relatively prime.
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1
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1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
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OFFSET
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1,11
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LINKS
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EXAMPLE
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gcd(11!-1,2^11-1) = 23, gcd(11!-2, 2^11-2) = 2, gcd(11!-3,2^11-3) = 1, so a(11) = 3.
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MATHEMATICA
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Table[m = 1; While[GCD[n! - m, 2^n - m] != 1, m++]; m, {n, 1, 140}]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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