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The smallest n-digit number where last k digits are divisible by k-th prime for k = 1..n.
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%I #15 Aug 07 2013 18:22:10

%S 0,12,100,1190,10560,217490,1377000,18319800,224246090

%N The smallest n-digit number where last k digits are divisible by k-th prime for k = 1..n.

%C There are 9 terms in the sequence and 9-digit number 224246090 is the last number to satisfy the requirements.

%e There are five one-digit numbers divisible by first prime and smallest is 0 so a(1)=0. For 2-digit numbers, the tens digit must make it divisible by 3 which gives 12 as smallest to satisfy the requirement so a(2)=12.

%Y Cf. A079212.

%K nonn,base,fini,full

%O 1,2

%A _Shyam Sunder Gupta_, Aug 07 2013