OFFSET
1,1
COMMENTS
There are exactly 30 such palindromic dates between Jan 1 00 and Dec 31 99 (see b-file for the complete list).
See A210887 for the number of days after 'Mar 1 00' to get such a palindromic date.
LINKS
Hieronymus Fischer, Table of n, a(n) for n = 1..30
Index entries for linear recurrences with constant coefficients, signature (1,0,1,-1).
FORMULA
a(n) = DDMMYY_date('Mar 1 00' + A210887(n)).
From Chai Wah Wu, Feb 03 2021: (Start)
a(n) = a(n-1) + a(n-3) - a(n-4) for n > 7.
G.f.: x*(100001*x^6 - 391094*x^3 + 100001*x^2 + 100001*x + 101101)/(x^4 - x^3 - x + 1). (End)
a(n) ~ 10010*n/3. - Charles R Greathouse IV, May 28 2026
EXAMPLE
The first palindromic date in DD.MM.YY format after 'Jan 01 00' is a(1)=101101 (='10.11.01' = 'Nov 10 01' = 'Mar 01 00' + A210887(1) days);
The sixth palindromic date in DD.MM.YY format after 'Jan 01 00' is a(6)=211112 (='21.11.12' = 'Nov 21 12' = 'Mar 01 00' + A210887(6) days).
The last (30th) palindromic date in DD.MM.YY format after 'Jan 01 00' is a(30)=291192 (='29.11.92' = 'Nov 29 92' = 'Mar 01 00' + A210887(30) days).
PROG
(PARI) a(n)=if(n>3, (10010*n+11*[52116, -610, 25753][n%3+1])/3, 100001*n+1100) \\ Charles R Greathouse IV, May 28 2026
CROSSREFS
KEYWORD
nonn,base,easy,changed
AUTHOR
Hieronymus Fischer, Apr 01 2012
STATUS
approved
