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Number of 8's in the last section of the set of partitions of n.
3

%I #22 Dec 01 2013 13:35:02

%S 0,0,0,0,0,0,0,1,0,1,1,2,2,4,4,8,8,13,15,23,26,38,45,63,74,101,120,

%T 160,191,248,298,383,457,579,694,868,1038,1287,1536,1890,2251,2746,

%U 3267,3962,4698,5665,6706,8043,9496,11337,13354,15876,18657,22089

%N Number of 8's in the last section of the set of partitions of n.

%C Zero together with the first differences of A024792. Also number of occurrences of 8 in all partitions of n that do not contain 1 as a part. For the definition of "last section of n" see A135010. It appears that the sums of eight successive terms give the partition numbers A000041.

%F It appears that A000041(n) = Sum_{j=1..8} a(n+j), n >= 0.

%o (Sage) A206558 = lambda n: sum(list(p).count(8) for p in Partitions(n) if 1 not in p)

%Y Column 8 of A182703 and of A194812.

%Y Cf. A000041, A135010, A138121, A182712-A182714, A206555- A206557, A206559, A206560.

%K nonn

%O 1,12

%A _Omar E. Pol_, Feb 09 2012