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A201106 a(n) = binomial(n^2,3)/(2*n). 1

%I #26 Jul 15 2021 11:01:22

%S 0,1,14,70,230,595,1316,2604,4740,8085,13090,20306,30394,44135,62440,

%T 86360,117096,156009,204630,264670,338030,426811,533324,660100,809900,

%U 985725,1190826,1428714,1703170,2018255,2378320,2788016,3252304,3776465,4366110,5027190

%N a(n) = binomial(n^2,3)/(2*n).

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (6,-15,20,-15,6,-1).

%F a(n) = (n-1)*n*(n^3+n^2-2*n-2)/12.

%F G.f.: x^2*(1+8*x+x^2) / (x-1)^6. - _R. J. Mathar_, Nov 28 2011

%p seq(binomial(n^2,3)/(2*n), n=1..29)

%Y Cf. A264853 (first differences).

%K nonn,easy

%O 1,3

%A _Gary Detlefs_, Nov 26 2011

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Last modified May 10 23:01 EDT 2024. Contains 372388 sequences. (Running on oeis4.)