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a(n) = round((9*n+1/n)^n).
1

%I #10 Jun 09 2023 23:27:00

%S 10,342,20421,1726760,188665362,25257633874,4001931082418,

%T 732295911309956,151957855559538858,35257207352182955135,

%U 9044237131202445725077,2541585712463861383036826

%N a(n) = round((9*n+1/n)^n).

%H Vincenzo Librandi, <a href="/A197982/b197982.txt">Table of n, a(n) for n = 1..250</a>

%t Table[Round[(9n+1/n)^n],{n,20}] (* _Harvey P. Dale_, Jan 29 2013 *)

%o (Magma) [Round((9*n+1/n)^n): n in [1..20]]

%Y Cf. A014056, A197598.

%K nonn

%O 1,1

%A _Vincenzo Librandi_, Oct 20 2011