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a(n) = ceiling((n+1/3)^n).
1

%I #11 Sep 08 2022 08:45:59

%S 2,6,38,353,4316,64535,1140539,23256804,537441242,13880477011,

%T 396218076728,12386985584176,420923890579262,15447592770126360,

%U 608903758014263549,25656487848259583961,1150788495459483630200,54745172171004903538415

%N a(n) = ceiling((n+1/3)^n).

%H Vincenzo Librandi, <a href="/A197972/b197972.txt">Table of n, a(n) for n = 1..300</a>

%t Table[Ceiling[(n+1/3)^n],{n,20}] (* _Harvey P. Dale_, Nov 09 2014 *)

%o (Magma) [Ceiling((n+1/3)^n): n in [1..20]]

%Y Cf. A014058, A197910.

%K nonn

%O 1,1

%A _Vincenzo Librandi_, Oct 20 2011