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A196191 G.f. satisfies A(x) = 1/Product_{n>=1} (1 - x^n/A(x^n)). 4

%I #7 Mar 30 2012 18:37:29

%S 1,1,1,1,1,2,1,3,2,3,4,4,4,6,7,7,8,10,11,12,14,17,18,20,22,26,30,31,

%T 37,39,46,49,54,61,69,74,82,91,100,114,119,136,149,159,176,193,214,

%U 227,255,276,303,324,360,394,420,462,496,548,590,638,692,749,812,874,946,1035,1115,1191,1292,1395,1503

%N G.f. satisfies A(x) = 1/Product_{n>=1} (1 - x^n/A(x^n)).

%C The rate of growth of this sequence is surprisingly slow.

%H Paul D. Hanna, <a href="/A196191/b196191.txt">Table of n, a(n) for n = 0..512</a>

%e G.f.: A(x) = 1 + x + x^2 + x^3 + x^4 + 2*x^5 + x^6 + 3*x^7 + 2*x^8 +...

%e where

%e A(x) = 1/((1 - x/A(x)) * (1 - x^2/A(x^2)) * (1 - x^3/A(x^3)) *...).

%o (PARI) {a(n)=local(A=1+x); for(i=1, n, A=1/prod(k=1, n, (1-x^k/subst(A, x, x^k+x*O(x^n))))); polcoeff(A, n)}

%Y Cf. A050383, A196192.

%K nonn

%O 0,6

%A _Paul D. Hanna_, Sep 28 2011

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