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Primes p=6k+1 such that p^2 | n^n+(n+1)^(n+1) for some n=4 (mod 6) but not p | n^2+n+1.
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%I #16 Nov 12 2019 09:24:55

%S 907,1039,1093,1231,1303,1531,1993,2377,2647,2713,2731,3001,3331,4003,

%T 4177,4243,4339,4447

%N Primes p=6k+1 such that p^2 | n^n+(n+1)^(n+1) for some n=4 (mod 6) but not p | n^2+n+1.

%H D. Broadhurst, <a href="http://groups.yahoo.com/group/primenumbers/message/23431">Re: Square factors of n^n+(n+1)^(n+1) [starting with 907^2]</a>, on yahoo group "primenumbers", Oct 12 2011

%H David Broadhurst and others, <a href="/A195987/a195987.txt">Square factors of n^n+(n+1)^(n+1) [starting with 907^2]</a>, digest of 81 messages in primenumbers Yahoo group, Oct 12 - Nov 29, 2011.

%K nonn,more

%O 1,1

%A _M. F. Hasler_, Oct 12 2011