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Round(Pi^(n+1)/(Pi^2 + 1)).
0

%I #13 Apr 22 2012 15:36:55

%S 0,1,3,9,28,88,278,873,2742,8616,27067,85032,267137,839237,2636540,

%T 8282934,26021606,81749286,256822958,806833117,2534740992,7963123679,

%U 25016890851,78592880513,246906816043,775680639401,2436872598275,7655661052475,24050968520829

%N Round(Pi^(n+1)/(Pi^2 + 1)).

%C a(n+1)/a(n) converges to Pi.

%F a(n) = round(Pi^(n+1)/(Pi^2 + 1)).

%e a(4) = 28 because (Pi^5)/(Pi^2 + 1) = 28.1537095089....

%t Table[Round[Pi^(n + 1)/(Pi^2 + 1)], {n, 0, 28}]

%o (PARI) for(n=0, 28, print1(round(Pi^(n+1)/(Pi^2+1)), ", "))

%Y Another version of A090426.

%Y Cf. A000796, A170953.

%K nonn

%O 0,3

%A _Arkadiusz Wesolowski_, Apr 22 2012