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A194906 Rectangular array, by antidiagonals: row n gives the positions of n in the fractal sequence A194905; an interspersion. 4

%I #5 Mar 30 2012 18:57:44

%S 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,

%T 27,28,30,31,32,33,34,35,36,29,38,40,41,42,43,44,45,37,39,47,49,51,52,

%U 53,54,55,46,48,50,57,59,61,63,64,65,66,56,58,60,62,68,70,72

%N Rectangular array, by antidiagonals: row n gives the positions of n in the fractal sequence A194905; an interspersion.

%C See A194832 for a general discussion.

%e Northwest corner:

%e 1...2...4...7...11..16..22

%e 3...5...8...12..17..23..31

%e 6...9...13..18..24..32..41

%e 10..14..19..25..33..42..52

%e 15..20..26..34..43..53..64

%t r = Pi;

%t t[n_] := Table[FractionalPart[k*r], {k, 1, n}];

%t f = Flatten[Table[Flatten[(Position[t[n], #1] &) /@

%t Sort[t[n], Less]], {n, 1, 20}]] (* A194905 *)

%t TableForm[Table[Flatten[(Position[t[n], #1] &) /@

%t Sort[t[n], Less]], {n, 1, 15}]]

%t row[n_] := Position[f, n];

%t u = TableForm[Table[row[n], {n, 1, 20}]]

%t g[n_, k_] := Part[row[n], k];

%t p = Flatten[Table[g[k, n - k + 1], {n, 1, 13},

%t {k, 1, n}]] (* A194906 *)

%t q[n_] := Position[p, n]; Flatten[Table[q[n],

%t {n, 1, 80}]] (* A194907 *)

%Y Cf. A194832, A194905, A194907.

%K nonn,tabl

%O 1,2

%A _Clark Kimberling_, Sep 05 2011

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Last modified April 23 03:30 EDT 2024. Contains 371906 sequences. (Running on oeis4.)