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Beatty sequence for (1/2)*sqrt(5); complement of A194152.
3

%I #5 Mar 30 2012 18:57:40

%S 1,2,3,4,5,6,7,8,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,

%T 29,30,31,32,33,34,35,36,38,39,40,41,42,43,44,45,46,48,49,50,51,52,53,

%U 54,55,57,58,59,60,61,62,63,64,65,67,68,69,70,71,72,73,74,76,77

%N Beatty sequence for (1/2)*sqrt(5); complement of A194152.

%t r=Sqrt[5]/2;

%t c[k_]:=Floor[k*r];

%t Table[c[k],{k,1,90}] (* A194151 *)

%t s=5+2*Sqrt[5];

%t d[k_]:=Floor[k*s];

%t Table[d[k],{k,1,90}] (* A194152 *)

%Y Cf. A194152.

%K nonn

%O 1,2

%A _Clark Kimberling_, Aug 17 2011