%I #12 Jul 03 2024 10:54:28
%S 0,1,1,1,23,1,1,1,2,1,2,3,5,2,1,30,18,1,2,1,2,4,2,399,2,2,3,1,2,1,4,1,
%T 1,4,2,1,2,2,12,1,3,1,3,1,2,6,1,1,1,43,1,1,1,4,1,1,16,16,1,8,1,3,3,7,
%U 1,4,25,1,4,1,1,4
%N Continued fraction of the number A191504 = 1/(1+1/(1+2/(1+3/(1+5/(1+7/(1+11/(...))))))), where the numerators > 1 are the primes.
%C The subsequence starting with the third (resp. second) term represents the continued fraction of the number A191815 = 1+2/(1+3/(1+5/(1+7/(1+11/(...))))) (resp. of 1+1/A191815).
%Y Cf. A191504 (decimal expansion), A191815.
%K nonn,cofr
%O 0,5
%A _M. F. Hasler_, Jun 17 2011
%E Offset changed by _Andrew Howroyd_, Jul 03 2024