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Integers in (2+A191113)/3; contains A191113 as a proper subsequence.
3

%I #4 Mar 30 2012 18:57:30

%S 1,2,4,6,8,10,14,16,22,28,38,40,46,54,62,64,72,82,86,110,112,118,136,

%T 150,158,160,182,184,190,200,214,244,246,254,256,326,328,334,342,352,

%U 406,438,446,448,456,470,472,478,542,544,550,568,584,598,630,638,640,726,730,734,736,758,760,766,840,854

%N Integers in (2+A191113)/3; contains A191113 as a proper subsequence.

%C See A191113.

%e A191113=(1,2,4,6,10,...), whence (2+A191113)/3=(1,4/2,2,8/3,4,...), so that, retaining only integers, A191146=(1,2,4,...).

%t (See A191113.)

%Y Cf. A191113, A191149.

%K nonn

%O 1,2

%A _Clark Kimberling_, May 27 2011