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a(n) = floor(n^((n-1)/2)).
4

%I #15 Sep 08 2022 08:45:57

%S 1,1,3,8,25,88,343,1448,6561,31622,161051,861979,4826809,28172943,

%T 170859375,1073741824,6975757441,46753733110,322687697779,

%U 2289733608959,16679880978201,124577080440588,952809757913927,7454684703958210

%N a(n) = floor(n^((n-1)/2)).

%H Bruno Berselli, <a href="/A190343/b190343.txt">Table of n, a(n) for n = 1..200</a>

%e a(6)=88 since floor(6^(5/2))=88.

%t Table[Floor[n^((n - 1)/2)], {n, 40}] (* _Vincenzo Librandi_, Mar 26 2013 *)

%o (Magma) [Floor(n^((n-1)/2)): n in [1..24]];

%o (PARI) for(n=1,20, print1(floor(n^((n-1)/2)), ", ")) \\ _G. C. Greubel_, Dec 30 2017

%Y Cf. A066642, A075364.

%K nonn

%O 1,3

%A _Bruno Berselli_, May 12 2011