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%I #14 Aug 03 2014 14:01:30
%S 1,2,3,4,5,6,7,8,9,11,15,20,22,24,33,40,42,44,48,51,55,60,66,77,80,84,
%T 88,99,102,108,111,114,117,120,126,132,135,144,150,153,156,162,171,
%U 180,192,195,198,201,204,207,210,216,222,225,228,234,240,243,252
%N Numbers n such that the mean of the digits in n is an integer m and n is divisible by m.
%C Subsequence of A061383. Supersequence of A010785.
%e 132 is in the sequence because it is divisible by the arithmetic mean of its digits, namely 2.
%t okQ[n_] := Module[{m = Mean[IntegerDigits[n]]}, IntegerQ[m] && Divisible[n, m]]; Select[Range[500], okQ] (* _T. D. Noe_, May 09 2011 *)
%K nonn,base
%O 1,2
%A _Jaroslav Krizek_, May 07 2011
%E Corrected and extended by _T. D. Noe_, May 09 2011