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Positions of 1 in A190236; complement of A190237.
3

%I #10 Dec 28 2017 03:39:52

%S 1,3,9,11,17,19,21,27,29,35,37,43,45,51,53,55,61,63,69,71,77,79,85,87,

%T 95,97,103,105,111,113,119,121,129,131,137,139,145,147,153,155,161,

%U 163,165,171,173,179,181,187,189,195,197,199,205,207,213,215,221,223,229,231,239,241,247,249,255,257,263,265,273,275,281,283

%N Positions of 1 in A190236; complement of A190237.

%H G. C. Greubel, <a href="/A190238/b190238.txt">Table of n, a(n) for n = 1..2750</a>

%t u = 1/2; v = GoldenRatio;

%t f[n_] := Floor[n*u + n*v] - Floor[n*u] - Floor[n*v]

%t t = Table[f[n], {n, 1, 120}] (* A190236 *)

%t Flatten[Position[t, 0]] (* A190237 *)

%t Flatten[Position[t, 1]] (* A190238 *)

%K nonn

%O 1,2

%A _Clark Kimberling_, May 06 2011