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%I #5 Mar 31 2012 12:36:15
%S 0,2,4,6,12,0,12,38,42,12,20,78,152,136,0,30,148,462,928,550,40,42,
%T 240,1088,3388,4920,1892,0,56,380,2128,9394,24806,27508,7384,140,72,
%U 554,3850,22088,85480,182634,152358,26816,0,90,788,6474,45892,238836,787412
%N T(n,k)=Number of arrangements of n+1 nonzero numbers x(i) in -k..k with the sum of floor(x(i)/x(i+1)) equal to zero
%C Table starts
%C ...0......2........6........12.........20..........30...........42...........56
%C ...4.....12.......38........78........148.........240..........380..........554
%C ...0.....42......152.......462.......1088........2128.........3850.........6474
%C ..12....136......928......3388.......9394.......22088........45892........86416
%C ...0....550.....4920.....24806......85480......238836.......567774......1218778
%C ..40...1892....27508....182634.....787412.....2642358......7269852.....17692662
%C ...0...7384...152358...1350418....7250142....29261538.....93830584....260746932
%C .140..26816...852940..10077438...67449574...326423068...1218634086...3870426602
%C ...0.103288..4796962..75593372..630466648..3664621084..15936391068..57837221756
%C .504.386928.27117826.569975518.5926141678.41363200538.209537582772.869215927390
%H R. H. Hardin, <a href="/A189498/b189498.txt">Table of n, a(n) for n = 1..797</a>
%e Some solutions for n=7 k=5
%e .-5...-5...-5...-5...-5...-4...-5...-5...-5...-4...-5...-5...-5...-5...-5...-5
%e .-5...-5...-5...-5...-5...-5...-5...-5...-5...-5...-5...-5...-5...-5...-5...-5
%e ..3...-4....5....2....3...-4....4...-4...-3...-5....5....5....1....1....3....3
%e .-4....3...-4...-3....2...-3....3....5....1...-3...-4....2....4....2....1....2
%e .-2....2...-1...-4...-1...-5....1....4....1...-4...-2...-5....2....2...-1....5
%e ..4....5...-3....4...-5...-2...-2....3....2...-5....2....3...-5...-4...-5...-5
%e ..3...-2....2....2...-4....5...-4...-1....2....3....3....5...-5...-1....3...-2
%e ..5...-1....5....1...-4...-2....3...-4...-4....4....3....5...-2...-4....3....2
%Y Column 1 is A028329(n/2) for even n
%Y Row 1 is A002378(n-1)
%K nonn,tabl
%O 1,2
%A _R. H. Hardin_ Apr 23 2011