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Zero-one sequence based on the sequence n(n+1): a(A002378(k))=a(k); a(A078358(k))=1-a(k), a(1)=0.
3

%I #9 Dec 29 2012 18:02:55

%S 1,1,0,1,0,1,1,0,0,1,1,0,0,0,1,1,1,0,0,1,0,1,1,0,1,0,0,1,0,0,1,1,0,1,

%T 1,0,0,1,0,0,1,1,1,0,1,1,0,0,0,1,0,0,1,1,1,1,0,1,1,0,0,0,0,1,0,0,1,1,

%U 1,1,0,0,1,1,0,0,0,0,1,1,0,0,1,1,1,1,0,0,1,0,1,0,0,0,0,1,1

%N Zero-one sequence based on the sequence n(n+1): a(A002378(k))=a(k); a(A078358(k))=1-a(k), a(1)=0.

%t u[n_] := n(n+1); (*A002378*)

%t a[1] = 0; h = 128;

%t c = (u[#1] &) /@ Range[2h];

%t d = (Complement[Range[Max[#1]], #1] &)[c]; (*A078358*)

%t Table[a[d[[n]]] = 1 - a[n], {n, 1, h - 1}]; (*A189163*)

%t Table[a[c[[n]]] = a[n], {n, 1, h}] (*A189163*)

%t Flatten[Position[%, 0]] (*A189164*)

%t Flatten[Position[%%, 1]] (*A189165*)

%Y Cf. A188967, A189164, A189165.

%K nonn

%O 1

%A _Clark Kimberling_, Apr 17 2011